I am one of those nerdy guys who enjoy the physics behind the smoke and powder and thought there might be one or two other blackpowder geeks who want to know how much damage they are doing to them self and the object at the recieving end of the process. Here goes:

Recoil: Example #1

(muzzle velocity X bullet Grain weight) plus (velocity charge constant X powder charge in grains) divide by constant of 225400 = A

(A X gravitational constant) divided by gun weight in pounds= A1

(A1 X A1 Xgun weight in pounds) divided by constant of 64.32= Foot lb recoil.

Lets use a 30-06 since most of us have shot one and have a general idea of how the recoil feels.

(2,700(muzzle velocity) X 180(bullet grain)) + (4700 (constant) X 55(grains poowder))= 744,500. divide by 225400(constant)= 3.3

3.3 X 32.2(gravity constant)= 106.26.

106.26 divided by weight of gun 8 lbs= 13.2

13.2 X 13.2 X 8(gun weight)=1394

1394 divided by 64.32(constant)= 21.6 foot pounds of recoil.

example #2. A 50 caliber muzzlelaoder shooting 385 grain bullet, with 100 grains powder, a muzzle velocity of 1375, and a gun weight of 7.5 pounds.

(1375 mv X 385 bullet) plus (4700 X 100 gr.powder)=999375

999375 divided by 225400 Constant= 4.43

4.43 X 32.2 grav C=142.76

142.76 divided by 7.5 gun wt in lbs= 19.03

19.03 X 19.03 x 7.5 gn wt= 2716.87

2716.87 divided by 64.32 constant= 42.2 foot lbs recoil.

Now for the recieving end regarding foot lb energy delivered by the projectile.

Bullet velocity squared divide by 7000,Divide by 64.32 (constant) then multiply by bullet wt. in grains.

Example: 385 grain bullet traveling 1000 fps at 100 yards.

(1000 X 1000)=1000000.

1000000 divided by 7000 (gr/lb).=142.8

142.8 divided by 64.32 (constant) = 2.22

2.22 X 385 (bullet weight)= 855 foot pound energy at 100 yards.

Ain't math great!